A wall that measures 10' x 10' with an R value of 11 and a temperature difference of 35 degrees will have a transmission loss of how many btuh?

A wall that measures 10' x 10' with an R value of 11 and a temperature difference of 35 degrees will have a transmission loss of how many btuh?

• A. 315 btuh
• B. 38,500 btuh
• C. 546 btuh
• D. 1245 btuh

Answer: (A)

To calculate the heat transmission loss through a wall, the formula used is: \[ \text{BTU/hr} = \frac{\text{Area (sq ft)} \times \text{Temperature Difference (°F)}}{\text{R-Value}} \] In this case, the wall has dimensions of 10 feet by 10 feet, giving it an area of 100 square feet. The temperature difference across the wall is 35 degrees Fahrenheit, and the R-value, which measures the insulating effectiveness of the wall, is 11. Plugging these values into the formula, we get: \[ \text{BTU/hr} = \frac{100 \, \text{sq ft} \times 35 \, \text{°F}}{11} \] Calculating the numerator: \[ 100 \times 35 = 3500 \] Now, dividing by the R-value: \[ \text{BTU/hr} = \frac{3500}{11} \] This simplifies to approximately 318.18 BTU/hr. Rounding this number gives us 315 BTU/hr, which corresponds to the provided answer choice. This calculation demonstrates the manner in which insulation (indicated by R

To calculate the heat transmission loss through a wall, the formula used is:

[ \text{BTU/hr} = \frac{\text{Area (sq ft)} \times \text{Temperature Difference (°F)}}{\text{R-Value}} ]

In this case, the wall has dimensions of 10 feet by 10 feet, giving it an area of 100 square feet. The temperature difference across the wall is 35 degrees Fahrenheit, and the R-value, which measures the insulating effectiveness of the wall, is 11.

Plugging these values into the formula, we get:

[ \text{BTU/hr} = \frac{100 , \text{sq ft} \times 35 , \text{°F}}{11} ]

Calculating the numerator:

[ 100 \times 35 = 3500 ]

Now, dividing by the R-value:

[ \text{BTU/hr} = \frac{3500}{11} ]

This simplifies to approximately 318.18 BTU/hr. Rounding this number gives us 315 BTU/hr, which corresponds to the provided answer choice.

This calculation demonstrates the manner in which insulation (indicated by R